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In an adsorption experiment a graph between log `x/m` versus log `P` was fond to be linear with a slope of `45^@)`. The intercept on the log `x/m` axis was found to `0.70`. Calculate the amount of gas adsorbed per gram of charcoal under a pressure of `1` atm `[log5=0.70]`A. `5`B. `2`C. `3`D. `0` |
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Answer» Correct Answer - A `"log" x/m=logk+1/nlogP` `1/n=tan45^(@)` `:.n=1` `logk=0.70` `:.k=5` Now `x/m=KP^(1//m)` `5(1)^(1/1)=5` |
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