1.

In an AC circuit, resistance 50 Ω, inductance 0.3 H and capacitance 15 μF is connected to an AC voltage source 25 V, 50 Hz. Determine the phase difference between current and voltage.(a) 670(b) 540(c) 470(d) 770

Answer» Right choice is (a) 670

To explain: XL=2πfL,  XC=1/(2πfC)    f=50Hz and L=0.3H and C=15 μF

XL=2π(50)(0.3) = 94.25 ohm.

XC=1/(2π*50*15*10^-6) =  212.21 ohm.

tanϕ = |(XL-XC)|/R = (212.21-94.25)/50 = 2.3592

ϕ=67^0.


Discussion

No Comment Found

Related InterviewSolutions