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In an AC circuit, resistance 50 Ω, inductance 0.3 H and capacitance 15 μF is connected to an AC voltage source 25 V, 50 Hz. Determine the phase difference between current and voltage.(a) 670(b) 540(c) 470(d) 770 |
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Answer» Right choice is (a) 670 To explain: XL=2πfL, XC=1/(2πfC) f=50Hz and L=0.3H and C=15 μF XL=2π(50)(0.3) = 94.25 ohm. XC=1/(2π*50*15*10^-6) = 212.21 ohm. tanϕ = |(XL-XC)|/R = (212.21-94.25)/50 = 2.3592 ϕ=67^0. |
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