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In an A.P the sum of three consecutive terms is 30 and their product is 360. Find the terms. (terms are in ascending order) * |
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Answer» ONG>ANSWER: the 3 consecutive terms are 4,10,14 Step-by-step explanation: LET let 3 consecutive terms be a-d ,a ,a+d some are THREE consecutive terms is 30 then 3A = 30 which implies a = 10 product of three consecutive terms is 360 then (a-d )xa x (a + d) which implies a²-d² x a= 360 a²-d²=360/10 100-d²=36 -d²=-64 d=6 which implies a-d=4 a=6 a+d=14 therefore the three consecutive terms are 4,6,14 |
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