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In an A.P t5+t9=72and t7+t12=97 then write first three terms of A.P |
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Answer» Answer: Step-by-step EXPLANATION: Givent5+ t9=72 =a+4d+a+8d=72 =2a+12d=72---(1) t7+t12=97 =a+6d+a+11d=97 =2a+17d=97---(2) By elimination method, we get, a=6 and d=5. So the first three TERMS of the AP will be: 6,11,16... HOPE this may help you Mention any required correction in my answer Thank You!!! |
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