1.

In an A.P t5+t9=72and t7+t12=97 then write first three terms of A.P​

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Answer:

Step-by-step EXPLANATION:

Given

t5+ t9=72

=a+4d+a+8d=72

=2a+12d=72---(1)

t7+t12=97

=a+6d+a+11d=97

=2a+17d=97---(2)

By elimination method, we get, a=6 and d=5.

So the first three TERMS of the AP will be: 6,11,16...

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