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In an a.c. circuit, the applied voltage and flowing current are E=E_(0)sinomegat and I=I_(0)sin(omegat+pi/2) respectively. What is the average power consumed in one cycle in this circuit ? |
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Answer» Solution :Zero. [HINT : AVERAGE power consumed = `(E_(0))/(sqrt2).(I_(0))/(sqrt2)cospi/2=0`] |
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