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In an A.C. circuit, `E=100 sin (500 t)` volt and `I=1000 sin(500 t +(pi)/3) mA`. The power dissipated in the circuit isA. 10 WB. 100 WC. 50 WD. 25 W |
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Answer» Correct Answer - D Power = `E_(rms) xx I_(rms) xx cos theta` `=(100)/(sqrt(2)) xx (1000 xx 10^(-3))/(sqrt(2)) xx cos 60^(@) = 25 W`. |
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