In alitre flask at a temperature there are 2gm of H2 and 8gm of O2 .th

1.	In alitre flask at a temperature there are 2gm of H2 and 8gm of O2 .the mole fraction of O2 . Int the given mixture is X×10 power minus one .the value of x is
Answer» Solution: MOLE of A/(Mole of A + B) = Mole Fraction → MASS of HYDROGEN gas = 2 gram → Mole of hydrogen gas = 2 gram/2 g/mol → Mole of hydrogen gas = 1 mol → Mass of OXYGEN gas = 8 gram → Mole of oxygen gas = 8 gram/32 g/mol → Mole of oxygen gas = ¼ mol → Mole fraction of O₂ = Mole of O₂/(Mole of H₂ + O₂) → x × 10⁻¹ = (¼)/(1 + ¼) → x/10 = (1/4)/(5/4) → x/10 = 1/4 × 4/5 → x/10 = 1/5 → x = 2 Hence, VALUE of x is 2

In alitre flask at a temperature there are 2gm of H2 and 8gm of O2 .the mole fraction of O2 . Int the given mixture is X×10 power minus one .the value of x is

Answer»

Solution: MOLE of A/(Mole of A + B) = Mole Fraction

→ MASS of HYDROGEN gas = 2 gram

→ Mole of hydrogen gas = 2 gram/2 g/mol

→ Mole of hydrogen gas = 1 mol

→ Mass of OXYGEN gas = 8 gram

→ Mole of oxygen gas = 8 gram/32 g/mol

→ Mole of oxygen gas = ¼ mol

→ Mole fraction of O₂

= Mole of O₂/(Mole of H₂ + O₂)

→ x × 10⁻¹ = (¼)/(1 + ¼)

→ x/10 = (1/4)/(5/4)

→ x/10 = 1/4 × 4/5

→ x/10 = 1/5

→ x = 2