In ▲ABC, the bisectors ∠B and ∠C intersect each other at a point

1.	In ▲ABC, the bisectors ∠B and ∠C intersect each other at a point D. If ∠BDC = 104°, then the measure of ∠A is :
Answer» Answer: we know that sum of triangle is 180 ° then , ag A + ag B+ ag C = 180° GIVEN , agB+ ag C =104° agA+agB+ AGC = 180° agA +104° = 180° ag A = 180° - 104 ° ag A = 76 ° hence prove I hope this is clear then like this and put in brainly list

In ▲ABC, the bisectors ∠B and ∠C intersect each other at a point D. If ∠BDC = 104°, then the measure of ∠A is :

Answer»

Answer:

we know that

sum of triangle is 180 °

then , ag A + ag B+ ag C = 180°

GIVEN , agB+ ag C =104°

agA+agB+ AGC = 180°

agA +104° = 180°

ag A = 180° - 104 °

ag A = 76 °

hence prove

I hope this is clear

then like this and put in brainly list

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In ▲ABC, the bisectors ∠B and ∠C intersect each other at a point D. If ∠BDC = 104°, then the measure of ∠A is :​

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In ▲ABC, the bisectors ∠B and ∠C intersect each other at a point D. If ∠BDC = 104°, then the measure of ∠A is :