In ∆ABC, seg AD ⊥ seg BC DB = 3CD. Prove that :2AB2 = 2AC2 + BC2

1.	In ∆ABC, seg AD ⊥ seg BC DB = 3CD. Prove that :2AB2 = 2AC2 + BC2
Answer» In ∆ABC, seg AD ⊥ seg BC DB = 3CD. Prove that : 2AB²= 2AC²+ BC²

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