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In 🔺 ABC, p and q are the middle point of AB and AC, prove that PQ parallel to BC |
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Answer» Given: In triangle ABC, P and Q are the mid points of sides AB and AC. To Prove: PQ // (parallel to) BC Proof: In triangle ABC;AP = PB (coz P is the mid point of AB!)=> AP/PB = 1 Similarly; AQ/QC = 1(Q is the mid point of AC) Therefore, AP/PB = AQ/QC Thus, by the Converse of the Basic Proportionality Theorem, PQ//BC Hence Proved. |
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