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In 🔺 ABC, p and q are the middle point of AB and AC, prove that PQ parallel to BC

Answer»

Given: In triangle ABC, P and Q are the mid points of sides AB and AC.

To Prove: PQ // (parallel to) BC

Proof: In triangle ABC;AP = PB (coz P is the mid point of AB!)=> AP/PB = 1

Similarly; AQ/QC = 1(Q is the mid point of AC)

Therefore, AP/PB = AQ/QC

​Thus, by the Converse of the Basic Proportionality Theorem,

PQ//BC

Hence Proved.



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