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In ∆ ABC, if PQ || side BC, AP = 6, PB = 4 and AQ = 9, then find QC. |
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Answer» Step-by-step EXPLANATION: By Basic Proportionality Theorem AP/ PB = AQ / QC 6/4 = 9/ QC QC = 9×4 / 6 QC = 36/ 6 QC = 6 HERE IS YOUR ANSWER ......Thx.. |
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