1.

In ∆ ABC, if PQ || side BC, AP = 6, PB = 4 and AQ = 9, then find QC.

Answer»

Step-by-step EXPLANATION:

By Basic Proportionality Theorem

AP/ PB = AQ / QC

6/4 = 9/ QC

QC = 9×4 / 6

QC = 36/ 6

QC = 6

HERE IS YOUR ANSWER ......

Thx..



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