1.

In △ABC, circumradius, R=3. Let O be the circumcentre and H be the orthocentre, then the value of 164(AH2+BC2)(BH2+AC2)(CH2+AB2) is 3k, where k is

Answer» In ABC, circumradius, R=3. Let O be the circumcentre and H be the orthocentre, then the value of 164(AH2+BC2)(BH2+AC2)(CH2+AB2) is 3k, where k is


Discussion

No Comment Found