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In △ABC, ∠C = 90°. D is a point on CA from which a perpendicular drawn to AB meets it at E. If ∠EDA = ∠ABC, BC = a cm., AD = x cm., AE = y cm., BE = Z cm. then DE = ……..cm.(1) \(\frac{ay}{z+x}\)(2) \(\frac{az}{x+y}\)(3) \(\frac{ax}{y+z}\)(4) None of these |
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Answer» Correct option is (3) \(\frac{ax}{y+z}\) |
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