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In ∆ABC, BD and CD are internal bisectors of angleB and angleC respectively.Prove that 180° +y=2x. |
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Answer» in triangle ABCy+<B+<C=180<B+<<C=180-yin triangle BCDx+<B/2 +<C/2 =180x+(<B+<C)/2=180x+(180-y)/2 =1802x+180-y=3602x=180+y |
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