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In ∆ABC ∠B= 90°, AB= 9, BC= 4 then find AC=. |
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Answer» Answer: FOR PERIMETRE :- FOR ANGLE :-∠A = ∠45°,∠B = ∠45° Step-by-step EXPLANATION: FOR PERIMETRE :- perimetre of triangle = sum of all SIDES =9+4+x = 11+x =x=8 =8cm hence, AB = 9cm; BC = 4CM; AC = 8cm angle of triangle = sum all sides= 180° =180°-90° =90° hence, ∠A= 45° ; ∠B=90° ; ∠C=45° |
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