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In ∆ABC ∠B= 90°, AB= 9, BC= 4 then find AC=.​

Answer»

Answer:

FOR PERIMETRE :-

FOR ANGLE :-∠A = ∠45°,∠B = ∠45°

Step-by-step EXPLANATION:

FOR PERIMETRE :-

perimetre of triangle = sum of all SIDES

                                   =9+4+x

                                   = 11+x

                                   =x=8

                                  =8cm

hence, AB = 9cm; BC = 4CM; AC = 8cm

angle of triangle = sum all sides= 180°

                            =180°-90°

                            =90°

hence, ∠A= 45° ; ∠B=90° ; ∠C=45°



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