In ∆ABC, AD is a median and P is a point is AD such that AP : PD = 1 – InterviewSolution

1.	In ∆ABC, AD is a median and P is a point is AD such that AP : PD = 1 : 2 then the area of ∆ABP = (A) 1/2 × Area of ∆ABC (B) 2/3 × Area of ∆ABC (C) 1/3 × Area of ∆ABC (D) 1/6 × Area of ∆ABC
Answer» The correct option is (D).

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