In ∆ABC, AB=10cm & BC=15cm. A line is drawn from the vertex B to AC such that AD:DC=2:3. Angle(BDC)=130° & Angle(BCA)=30°. Then, Angle(ABC) is equal to-(A) 30°(B) 40°(C) 45°(D) 110°

In ∆ABC, AB=10cm & BC=15cm. A line is drawn from the vertex B to AC

1.	In ∆ABC, AB=10cm & BC=15cm. A line is drawn from the vertex B to AC such that AD:DC=2:3. Angle(BDC)=130° & Angle(BCA)=30°. Then, Angle(ABC) is equal to-(A) 30°(B) 40°(C) 45°(D) 110°
Answer» In ∆ABC, AB=10cm & BC=15cm. A line is drawn from the vertex B to AC such that AD:DC=2:3. Angle(BDC)=130° & Angle(BCA)=30°. Then, Angle(ABC) is equal to- (A) 30° (B) 40° (C) 45° (D) 110°