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In AABC, if AD is the median, then show that AB2+AC2 2(AD+BD2) |
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Answer» AD is median, So BD=DC. AB^2= AE^2+BE^2 AC^2 = AE^2+EC^2 Adding both, AB^2+AC^2 = 2AE^2+BE^2+CE^2 = 2(AD^2-ED^2)+(BD-ED)^2+(DC+ED)^2 = 2AD^2-2ED^2+BD^2+ED^2-2BD.ED+DC^2+ED^2+2CD.ED = 2AD^2+BD^2+CD^2 = 2(AD^2+ BD^2) hit like if you find it useful |
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