In a young's double slit experiment, the distance between slits S1 and S2 is d and distance of slit plane from the screen is D(>>d). The point source of light (s) is placed a distance d2 below the principal axis and the slits S1 and S2 are located symmetrically with respect to the principal axis of the lens. Focal length of the lens is f(>>d). The distance of the central maxima of the fringe pattern from the centre (O) of the screen is found to be Ddxf. The value of 4x is

In a young's double slit experiment, the distance between slits S1 and

1.	In a young's double slit experiment, the distance between slits S1 and S2 is d and distance of slit plane from the screen is D(>>d). The point source of light (s) is placed a distance d2 below the principal axis and the slits S1 and S2 are located symmetrically with respect to the principal axis of the lens. Focal length of the lens is f(>>d). The distance of the central maxima of the fringe pattern from the centre (O) of the screen is found to be Ddxf. The value of 4x is
Answer» In a young's double slit experiment, the distance between slits $S_{1}$ and $S_{2}$ is $d$ and distance of slit plane from the screen is $D (>> d)$ . The point source of light (s) is placed a distance $\frac{d}{2}$ below the principal axis and the slits $S_{1}$ and $S_{2}$ are located symmetrically with respect to the principal axis of the lens. Focal length of the lens is $f (>> d)$ . The distance of the central maxima of the fringe pattern from the centre $(O)$ of the screen is found to be $\frac{D d}{x f}$ . The value of $4 x$ is

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