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In a Young's double-slit experiment, the distance between the two identical slits is 6.1 times larger than the slit width. Then the number of intensity maxima observed within the central maximum of the single slit diffraction pattern is : |
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Answer» 3 `d = 6.1 x` width of CENTRAL MAXIMA for single slit `omega_0 = (2D lambda)/x` If n maxima is OBSERVED by Young.s double-slit in central maxima of single slit `n((lambda D)/(d)) = (2 D lambda)/x` `implies n = 6.1 xx 2 = 12.2 ~~ 12` |
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