In a Venturi-meter through which water is flowing, the speed of water

1.	In a Venturi-meter through which water is flowing, the speed of water through the wider tube is 2×10^-2 m/s and the height of the liquid in the manometer is 5.1 mm. The density of water is 1000 Kg/m^3. Find the speed of water through the narrow tube.
Answer» ANSWER: The height difference between the POINTS X and y is 5.1 mm Therefore, the pressure difference between the 2 points will be, P=ρgh P=1×1000×0.51 P = 510 Applying Bernoulli's theorem, δP+0.5ρδv 2 =0 δP=510 510=0.5×1×(V 2 2 −2 2 ) Hence, v 2 2 =1024 or v 2 =32cm/sec

In a Venturi-meter through which water is flowing, the speed of water through the wider tube is 2×10^-2 m/s and the height of the liquid in the manometer is 5.1 mm. The density of water is 1000 Kg/m^3. Find the speed of water through the narrow tube.

Answer»

ANSWER:

The height difference between the POINTS X and y is 5.1 mm

Therefore, the pressure difference between the 2 points will be,

P=ρgh

P=1×1000×0.51

P = 510

Applying Bernoulli's theorem,

δP+0.5ρδv

δP=510

510=0.5×1×(V

−2

)

Hence, v

=1024 or v

=32cm/sec

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In a Venturi-meter through which water is flowing, the speed of water through the wider tube is 2×10^-2 m/s and the height of the liquid in the manometer is 5.1 mm. The density of water is 1000 Kg/m^3. Find the speed of water through the narrow tube.​

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In a Venturi-meter through which water is flowing, the speed of water through the wider tube is 2×10^-2 m/s and the height of the liquid in the manometer is 5.1 mm. The density of water is 1000 Kg/m^3. Find the speed of water through the narrow tube.