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In a uniform magneitc field of induced B a wire in the form of a semicircle of radius r rotates about the diameter of hte circle with an angular frequency `omega`. The axis of rotation is perpendicular to hte field. If the total resistance of hte circuit is R, the mean power generated per period of rotation isA. `(Bpir^(2)omega)/(2R)`B. `((Bpir^(2)omega)^(2))/(8R)`C. `((Bpiromega)^(2))/(2R)`D. `((Bpiromega^(2))^(2))/(8R)` |
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Answer» Correct Answer - B `phi=B(pi r^(2))/(2)cos omegat` `:. epsi=-(dphi)/(dt)=(1)/(2) B pi r^(2) omega sin omegat` `:.P=epsi^(2)/(R)=(B^(2)pi^(2)r^(4)omega^(2)sin^(2)omegat)/(4R)` `:. ltPgt=((Bpir^(2)omega)^(2))/(8R)" " ( :.ltsin^(2)omegatgt=(1)/(2))` |
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