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In a triangle (x+y+z)(y+z-k)=kyz then value of k is |
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Answer» Answer: As given , x, y and z are integers. y + z - x= constant y + z- x = K (z+x-y)(x+y-z) VARIES y z. →(x+z-y)[x-(z-y)]= P y z ⇒ x² - (z-y)²= P y z→→→→ Using Identity A²- B²=(A-B)(A+B) ⇒x² - (z-y)²- 4 y z= P y z - 4 y z ⇒x²- z²-y²+2 y z - 4 y z=(P-4) y z ⇒x²- (y+z)²= M y z⇒⇒P-4= M ⇒(x-y-z)(x+y+z)=M y z-----(1)→→→→ Using Identity A²- B²=(A-B)(A+B) As , y + z - x= k x-y-z= -k= N Putting the value of , x-y-z in equation (1) N (x+y+z)=M y z x+y+z= y z x + y + z= D y z, where = D Hence, (x+y+z)varies yz. Step-by-step explanation: plz make mem brainliest
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