1.

In a triangle Par right angled at QPQ-3 cm and PR = 9cmm, find the angle P​

Answer»

:

In ΔPQR; LQ=90

o

PQ=3cm; PR=6cm

QR=

6

2

−3

2

=3

3

SIN(LQPR)=

PR

QR

=

6

3

3

=

2

3

So, LQPR=60

o

⇒ LQRP=30

o



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