In a triangle ABC ,Z is the mid point of BC. If BX and CY are perpendi

1.	In a triangle ABC ,Z is the mid point of BC. If BX and CY are perpendicular to a line through A then prove that XZ=YZ
Answer» ANSWER: From the diagram attached, since bx and cy are perpendiculars to a line passing through the vertex a, it FOLLOWS that xy is parallel to bc Again, from the diagram, bx = cy ANGLE XBZ = angle ycz = 90 degrees Since z is the mid-point of bc, it follows that bz = zc From the forgoing, triangle xbz is congruent to triangle ycz (SSS) Therefore, xyz Step-by-step explanation:

In a triangle ABC ,Z is the mid point of BC. If BX and CY are perpendicular to a line through A then prove that XZ=YZ

Answer»

From the diagram attached, since bx and cy are perpendiculars to a line passing through the vertex a, it FOLLOWS that xy is parallel to bc

Again, from the diagram, bx = cy

ANGLE XBZ = angle ycz = 90 degrees

Since z is the mid-point of bc, it follows that bz = zc

From the forgoing, triangle xbz is congruent to triangle ycz (SSS)

Therefore, xyz Step-by-step explanation: