In a \triangle ABC, P, and Q are respectively, the mid points of AB and BC and R is the mid point of AP. Prove that (i)ar(△PBQ)=ar(△ARC)(ii)ar(PRQ)=12ar(△ARC)(iii)ar(△RQc)=38ar(△ABC)

In a \triangle ABC, P, and Q are respectively, the mid points of AB a

1.	In a \triangle ABC, P, and Q are respectively, the mid points of AB and BC and R is the mid point of AP. Prove that (i)ar(△PBQ)=ar(△ARC)(ii)ar(PRQ)=12ar(△ARC)(iii)ar(△RQc)=38ar(△ABC)
Answer» In a \triangle ABC, P, and Q are respectively, the mid points of AB and BC and R is the mid point of AP. Prove that $(i) a r (△ P B Q) = a r (△ A R C) (i i) a r (P R Q) = \frac{1}{2} a r (△ A R C) (i i i) a r (△ R Q c) = \frac{3}{8} a r (△ A B C)$