In a triangle ABC, median AD and CE are drawn. If AD=5,∠DAC=π8 and ∠ACE=π4, and the area of the triangle ABC is equal to Δ, then 3Δ is equal to:

In a triangle ABC, median AD and CE are drawn. If AD=5,∠DAC=π8 and

1.	In a triangle ABC, median AD and CE are drawn. If AD=5,∠DAC=π8 and ∠ACE=π4, and the area of the triangle ABC is equal to Δ, then 3Δ is equal to:
Answer» In a triangle $A B C$ , median $A D$ and $C E$ are drawn. If $A D = 5, ∠ D A C = \frac{π}{8}$ and $∠ A C E = \frac{π}{4},$ and the area of the triangle $A B C$ is equal to $Δ$ , then $3 Δ$ is equal to: