In a triangle ABC if cotA2cotB2=c,cotB2cotC2=a and cotC2cotA2=b then 1

1.	In a triangle ABC if cotA2cotB2=c,cotB2cotC2=a and cotC2cotA2=b then 1s−a+1s−b+1s−c=
Answer» In a triangle $A B C$ if $cot \frac{A}{2} cot \frac{B}{2} = c, cot \frac{B}{2} cot \frac{C}{2} = a and cot \frac{C}{2} cot \frac{A}{2} = b$ then $\frac{1}{s - a} + \frac{1}{s - b} + \frac{1}{s - c} =$

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In a triangle ABC if cotA2cotB2=c,cotB2cotC2=a and cotC2cotA2=b then 1s−a+1s−b+1s−c=

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