1.

In a triangle ABC if AB + BC equal 10 cm BC + CA = 12 CM CA + ABequal 16cm what is the parameter

Answer»

AB+BC=10--------(1)
BC+CA=12--------(2)
CA+AB=16--------(3)

(1)+(2)+(3)
AB+BC+BC+CA+CA+AB=10+12+16
2AB+2BC+2CA=38
2(AB+BC+CA)=38
AB+BC+CA=38/2
AB+BC+CA=19
The PERIMETER of the TRIANGLE ABC=19cm



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