1.

In a triangle ABC, cosec A (sin B cos C + cos B sin C) equals

Answer»

\implies

EXPLANATION:

We have,

CSCA(sinBcosC+cos B SIN C),

=cscAsin(B+C),

=cscAsin(π−A)...[as, in ΔABC,A+B +C=π],

=cscA⋅sinA,

=1.



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