In a triangle ABC, AB = AC and D is a point on side AC such that BC = AC × CD. Prove that BD = BC.

In a triangle ABC, AB = AC and D is a point on side AC such that BC =

1.	In a triangle ABC, AB = AC and D is a point on side AC such that BC = AC × CD. Prove that BD = BC.
Answer» In a triangle ABC, AB = AC and D is a point on side AC such that BC = AC $\times$ CD. Prove that BD = BC.