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In a triangle ABC 2ac sin1/2(A-B+C)=need help guysdon't spam plzand don't copy from Google irreverent answers 33 answers will be reported |
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Answer» Answer: a²-b²+c²Explanation: We KNOW that,A + B + C = 180°A + C - B = 180 - 2Bnow2ac sin (1/2(A-B+C))=2ac sin (90 °-B)=2ac COS B =(2 ac *(a²-b²+c²))/2ac= a²-b²+c²Please mark it brainliest! |
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