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In a triangle ABC 2ac sin1/2(A-B+C)=need help guysdon't spam plzand don't copy from Google irreverent answers 33 answers will be reported ​

Answer»

Answer:

a²-b²+c²

Explanation:

We KNOW that,

A + B + C = 180°

A + C - B = 180 - 2B

now

2ac sin (1/2(A-B+C))

=2ac sin (90 °-B)

=2ac COS B =(2 ac *(a²-b²+c²))/2ac

= a²-b²+c²

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