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In a trapezium ABCD, AB | | DC and DC = 2AB. EF | | AB, where E and F lie on BC and AD respectivelysuch thatDiagonal DB intersects EF at G. Prove that,BE 4EC 37EF-11AB. |
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Answer» given DC = 2 ABDraw BH parallel to AD. H will be the middle point of DC as AB = DH.Sin EF || AB, FI = AB TheΔBHC andΔBIE are similar as the correspondingsides are parallel.So IE / HC = BE / BC IE = HC * BE / BC = y * 4x/7x = 4 y /7 EF = FI + IE= y + 4 y /7 = 11 y / 7 so 7 EF = 11 AB |
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