In a thermodynamic process on an ideal monatomic gas, the infinitesima

In a thermodynamic process on an ideal monatomic gas, the infinitesimal heat absorbed by the gas is given by TΔX, where T is temperature of the system and ΔX is the infinitesimal change in a thermodynamic quantity X of the system. For a mole of monatomic ideal gas X=32Rln(TTA)+Rln(VVA). Here, R is gas constant, V is volume of gas, TA and VA are constants.The List-I below gives some quantities involved in a process and List-II gives some possible values of these quantities. List-I List-II(i)Work done by the system in process 1→2→3(P)13RT0ln2(ii)Change in intermal energy in process 1→2→3(Q)13RT0(iii)Heat absorbed by the system in process 1→2→3(R)RT0(iv)Heat absotbed by the system in process 1→2(S)43RT0 (T)13RT0(3+ln2) (U)56RT0If the process carricd out on one mole of monoatomic ideal gas is as shown in figure in the PV-diagram with P0V0=13RT0, the correct match is,

Answer»

In a thermodynamic process on an ideal monatomic gas, the infinitesimal heat absorbed by the gas is given by $T Δ X$ , where $T$ is temperature of the system and $Δ X$ is the infinitesimal change in a thermodynamic quantity $X$ of the system. For a mole of monatomic ideal gas $X = \frac{3}{2} R ln (\frac{T}{T_{A}}) + Rln (\frac{V}{V_{A}}) .$ Here, $R$ is gas constant, $V$ is volume of gas, $T_{A}$ and $V_{A}$ are constants.

The List-I below gives some quantities involved in a process and List-II gives some possible values of these quantities.

	List-I		List-II
(i)	Work done by the system in process $1 \to 2 \to 3$	(P)	$\frac{1}{3} {R T}_{0} ln 2$
(ii)	Change in intermal energy in process $1 \to 2 \to 3$	(Q)	$\frac{1}{3} {R T}_{0}$
(iii)	Heat absorbed by the system in process $1 \to 2 \to 3$	(R)	${R T}_{0}$
(iv)	Heat absotbed by the system in process $1 \to 2$	(S)	$\frac{4}{3} {R T}_{0}$
		(T)	$\frac{1}{3} {R T}_{0} (3 + ln 2)$
		(U)	$\frac{5}{6} {R T}_{0}$

If the process carricd out on one mole of monoatomic ideal gas is as shown in figure in the PV-diagram with $P_{0} V_{0} = \frac{1}{3} {R T}_{0}$ , the correct match is,

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