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In a steady-state reactive system, NaOH and HCl are supplied to the system both at the rate of 100 mole/min, then what is the rate of NaCl produced?(a) 100 mole/min(b) 200 mole/min(c) 300 mole/min(d) 400 mole/min |
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Answer» The correct option is (b) 200 mole/min Explanation: As the system is in steady-state, rate of product = rate of feed, => rate of NaCl = 100 + 100 = 200 mole/min. |
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