1.

In a solution of 7.8 g benzene (C_(6)H_(6)) and 46.0 g toluene (C_(6)H_(5)CH_(3)) the mole fraction of benzene is :

Answer»

`1//6`
`1//5`
`1//2`
`1//3`

SOLUTION :MOLE fraction of`C_(6)H_(6)=(7.8//78)/(7.8/78+46/92)=1/6`


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