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In a simultaneous throw of a pair of dice, find the probability of getting:a) 7 as a sum b) a doublet of odd number c) not a doubletd) an odd number on the first dicePlz give answer in steps

Answer»

Given :   a simultaneous throw of a pair of dice

To find :  the probability of getting

Solution:

a pair of dice thrown

total outcomes = 36

7 as sum  

( 1 , 6) , ( 2, 5) , ( 3 ,4 ) , ( 4 , 3) , ( 5 , 2) , ( 6 , 1)

Probability of  7 as sum   = 6/36 = 1/6

a DOUBLET of odd number

( 1, 1) , ( 3, 3) , ( 5 , 5)

probability of doublet of odd number  = 3/36 = 1/12

not a doublet

doublet = ( 1, 1) , ( 2, 2) , ( 3, 3) , ( 4, 4) , ( 5, 5) , ( 6, 6)

Probability of  not a doublet = 1  - 6/36  = 5/6

an odd number on the first dice

Probability  = 3/6  = 1/2

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