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In a simple pendulum length increases by 4% and increases by 2% then time period of simple pendulum |
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Answer» T=2π√l/g ΔT/T=1/2Δl/l + 1/2Δg/g ΔT/T*100=1/2*Δl/l*100 + 1/2*Δg/g*100 ΔT/T*100=4/2+2/2 =2+1 =3% |
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