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In a series resonant LCR circuit the voltage across R is 100 volts and R = `1 k(Omega) with C =2(mu)F`. The resonant frequency `(omega)` is `200 rad//s`. At resonance the voltage across L isA. 100 VB. 150 VC. 200 VD. 250 V |
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Answer» Correct Answer - D At resnonace, `omegaL = 1/(omegaC) and Z = R` Current through the circuit `I = (V_R)/(R) = 100/1000 = 0.1A` `:.` Voltage across L is given by `V_(L) = IX_(L) = I omega L` but `omega L = 1/(omega C)` `:. V_(L) = 1/(omega C)` `=(0.1)/(200 xx 2 xx 10^(-6)) = 1000/4 = 250V`. |
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