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In a series `RC` circuit with an AC source, `R = 300 Omega, C = 25 muF, epsilon_0= 50 V` and `v = 50/(pi) Hz`. Find the peak current and the average power dissipated in the circuit.A. 0.1 AB. 2 A/sC. 0.02 AD. 1A |
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Answer» Correct Answer - A `X_(C)=(1)/(2pifC)=(1)/(2pixx(50)/(pi)xx25xx10^(-6))` `=(1)/(25xx10^(-4))=4xx10^(2)=400Omega` `Z=sqrt(R^(2)+X_(C)^(2))=sqrt(9xx10^(4)+16xx10^(4))` `Z=5xx10^(2)=500Omega` `I_(0)=(e_(0))/(Z)=(50)/(500)=0.1A` |
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