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In a series circuit `C=2muF,L=1mH` and `R=10 Omega`, when the current in the circuit is maximum, at that time the ratio of the energies stored in the capacitor and the inductor will beA. `1:2`B. `5:1`C. `1:5`D. `1:1` |
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Answer» Correct Answer - B Maximum current flows in a series L-C-R circuit, when the condition of resonance is satisfied. In that case, `X_(L) = X_(C) and Z = R and I = I_(max) = V/R = V/10 A` Energy stored in the inductor `E_(L) = 1/2 LI_(max)^(2) = 1/2 L ((V)/(10))^(2)` ........(1) and the energy stored in the capacitor `E_(C) = 1/2 CV^(2)` .......(2) `:. (E_L)/(E_C) = (1/2L((V)/(10))^(2))/(1/2CV^(2)) = L/100C` `=(10^(-3))/(100 xx 2 xx 10^(-6)) = 1000/200 = 5/1`. |
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