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In a series ac circuit, the instantaneous voltage V(t) and current I(t) are given by V(t)=5[cosωt+√3 sin ωt] I(t)=5[sin(ωt+π4)], then |
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Answer» In a series ac circuit, the instantaneous voltage V(t) and current I(t) are given by V(t)=5[cosωt+√3 sin ωt] |
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