1.

In a right triangle, the square of the hypotenuse is equal to the sum of the squares of other twsides.

Answer»

can show thata2+ b2= c2usingAlgebra:-

Take a look at this diagram ... it has that "abc" triangle in it (four of them actually):

Area of Whole Square

It is a big square, with each side having a length ofa+b, so thetotal areais:

A = (a+b)(a+b)

Area of The Pieces

Now let's add up the areas of all the smaller pieces:

First, the smaller (tilted) square has an area of:c2

Each of the four triangles has an area of:ab2

So all four of them together is:4ab2= 2ab

Adding up the tilted square and the 4 triangles gives:A = c2+ 2ab

Both Areas Must Be Equal

The area of thelarge squareis equal to the area of thetilted square and the 4 triangles. This can be written as:

(a+b)(a+b) = c2+ 2ab

NOW, let us rearrange this to see if we can get the pythagoras theorem:

Start with:(a+b)(a+b) = c2+ 2ab

Expand (a+b)(a+b):a2+ 2ab + b2= c2+ 2ab

Subtract "2ab" from both sides:a2+ b2= c2



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