In a right triangle, sum of the squares of two sides is equal to the s

1.	In a right triangle, sum of the squares of two sides is equal to the square of the hypotenuse. By following these steps of construction, (i) Draw a line segment PQ = 11 cm (ii) At P construct an angle of 60o and at Q, an angle of 45o. (iii) Bisect these angles. Let the bisectors of these angles intersect at a point A. (iv)Draw perpendicular bisectors DE of AP to intersect PQ at B and FG of AQ to intersect PQ at C. (v). Join AB and AC. Triangle ABC has been obtained. In this ABC,
Answer» In a right triangle, sum of the squares of two sides is equal to the square of the hypotenuse. By following these steps of construction, (i) Draw a line segment PQ = 11 cm (ii) At P construct an angle of 60o and at Q, an angle of 45^o. (iii) Bisect these angles. Let the bisectors of these angles intersect at a point A. (iv)Draw perpendicular bisectors DE of AP to intersect PQ at B and FG of AQ to intersect PQ at C. (v). Join AB and AC. Triangle ABC has been obtained. In this ABC,

In a right triangle, sum of the squares of two sides is equal to the square of the hypotenuse. By following these steps of construction, (i) Draw a line segment PQ = 11 cm (ii) At P construct an angle of 60o and at Q, an angle of 45o. (iii) Bisect these angles. Let the bisectors of these angles intersect at a point A. (iv)Draw perpendicular bisectors DE of AP to intersect PQ at B and FG of AQ to intersect PQ at C. (v). Join AB and AC. Triangle ABC has been obtained. In this ABC,

Answer»

In a right triangle, sum of the squares of two sides is equal to the square of the hypotenuse.

By following these steps of construction,

(i) Draw a line segment PQ = 11 cm

(ii) At P construct an angle of 60o and at Q, an angle of 45^o.

(iii) Bisect these angles. Let the

bisectors of these angles intersect at a point A.

(iv)Draw perpendicular bisectors DE of AP to intersect PQ at B and FG of AQ to intersect PQ at C.

(v). Join AB and AC. Triangle ABC has been obtained. In this ABC,