In a right triangle ABC right-angled at C,P and Q are the points on the sides CA and CB respectively,which divide these sides in the ratio 2:1. Prove that1. 9AQ^2= 9AC^2 +4BC^2.2. 9BP^2=9BC^2+4AC^2.3. 9(AQ^2+BP^2)=13AB^2.

In a right triangle ABC right-angled at C,P and Q are the points on th

1.	In a right triangle ABC right-angled at C,P and Q are the points on the sides CA and CB respectively,which divide these sides in the ratio 2:1. Prove that1. 9AQ^2= 9AC^2 +4BC^2.2. 9BP^2=9BC^2+4AC^2.3. 9(AQ^2+BP^2)=13AB^2.
Answer» In a right triangle ABC right-angled at C,P and Q are the points on the sides CA and CB respectively,which divide these sides in the ratio 2:1. Prove that 1. 9AQ^2= 9AC^2 +4BC^2. 2. 9BP^2=9BC^2+4AC^2. 3. 9(AQ^2+BP^2)=13AB^2.