In a right-angled triangle ABC, right angled at B, AB =х2BC = x + 2 a

1.	In a right-angled triangle ABC, right angled at B, AB =х2BC = x + 2 and AC = x + 3. Findvalue of x.
Answer» Step-by-step explanation: Given : A triangle right angled at B. AB=x−3,BC=x+4,AC=x+6 Thus, AC 2 =AB 2 +BC 2 (PYTHAGORAS THEOREM) (x+6) 2 =(x−3) 2 +(x+4) 2 x 2 +12x+36=x 2 −6x+9+x 2 +8x+16 x 2 −10x−11=0 x 2 −11x+x−11=0 x(x−11)+1(x−11)=0 (x+1)(x−11)=0 x=11,−1 Neglecting the negative value, x=11 thus, AB=8 cm, AC=17 cm and BC=15 cm

In a right-angled triangle ABC, right angled at B, AB =х2BC = x + 2 and AC = x + 3. Findvalue of x.

Answer»

Step-by-step explanation:

Given : A triangle right angled at B.

AB=x−3,BC=x+4,AC=x+6

Thus, AC

=AB

+BC

(PYTHAGORAS THEOREM)

(x+6)

=(x−3)

+(x+4)

+12x+36=x

−6x+9+x

+8x+16

−10x−11=0

−11x+x−11=0

x(x−11)+1(x−11)=0

(x+1)(x−11)=0

x=11,−1

Neglecting the negative value, x=11

thus, AB=8 cm, AC=17 cm and BC=15 cm

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In a right-angled triangle ABC, right angled at B, AB =х2BC = x + 2 and AC = x + 3. Findvalue of x.​

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In a right-angled triangle ABC, right angled at B, AB =х2BC = x + 2 and AC = x + 3. Findvalue of x.