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In a right-angled triangle ABC, right angled at B, AB = x/2 ,BC = x + 2 and AC = x + 3. Findvalue of x. |
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Answer» Step-by-step explanation: (x/2)² + (x + 2)² = (x + 3)² x²/4 + x² + 4 + 4x = x² + 9 + 6X x²/4 + x² - x² + 4 - 9 + 4x - 6x = 0 x²/4 - 5 - 2x = 0 (x² - 20 - 8x)/4 = 0 x² - 8x - 20 = 0 x² - 10x + 2x - 20 = 0 x(x - 10) + 2(x - 10) = 0 (x + 2)(x - 10) = 0 x + 2 = 0 ⠀⠀⠀⠀⠀or ⠀⠀⠀⠀⠀⠀⠀x - 10 = 0 x = -2 ⠀⠀⠀⠀⠀⠀⠀or ⠀⠀⠀⠀⠀⠀⠀x = 10 Hope it helps u... |
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