In a right angled triangle ABC, angle B = 90°. If AB= 8, BC = 15,find

1.	In a right angled triangle ABC, angle B = 90°. If AB= 8, BC = 15,find the perimeter of ∆ ABC.
Answer» ong>Step-by-step explanation: AB = 8 units BC = 15 Units As angle B is 90° so , CB is hypotenuse so ACCORDING to Pythagoras theorem, H^2 = P^2 + B^2 CB^2 = AB^2 + BC^2 CB^2 = 8^2 + 15^2 = 64+225 = 289 CB = √289 CB = 17 Now, Perimeter of triangle = SUM of all sides so Perimeter of triangle ABC = AB+ BC+CB = 8+15+17 = 40 units

In a right angled triangle ABC, angle B = 90°. If AB= 8, BC = 15,find the perimeter of ∆ ABC.

Answer»

ong>Step-by-step explanation:

AB = 8 units

BC = 15 Units

As angle B is 90°

so , CB is hypotenuse

so ACCORDING to Pythagoras theorem,

H^2 = P^2 + B^2

CB^2 = AB^2 + BC^2

CB^2 = 8^2 + 15^2

= 64+225

= 289

CB = √289

CB = 17

Now, Perimeter of triangle = SUM of all sides

so Perimeter of triangle ABC = AB+ BC+CB

= 8+15+17

= 40 units

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In a right angled triangle ABC, angle B = 90°. If AB= 8, BC = 15,find the perimeter of ∆ ABC.​

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In a right angled triangle ABC, angle B = 90°. If AB= 8, BC = 15,find the perimeter of ∆ ABC.