In a right angle A= 90° , AD perpendicular to BC and ACD triangle = 1

1.	In a right angle A= 90° , AD perpendicular to BC and ACD triangle = 10cm² and AC = 9cm Find BC?
Answer» Answer: 18 Step-by-step EXPLANATION: tan 45 is 1 Tan 45=opposite side\adjacent side 1=CD/9 CD=9 CD=Because of a perpendicular line so BD=9 BC=CD+DB BC=9+9 BC=18

In a right angle A= 90° , AD perpendicular to BC and ACD triangle = 10cm² and AC = 9cm Find BC?

Answer»

Answer:

Step-by-step EXPLANATION:

tan 45 is 1

Tan 45=opposite side\adjacent side

1=CD/9

CD=9

CD=Because of a perpendicular line

so BD=9

BC=CD+DB

BC=9+9

BC=18

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In a right angle A= 90° , AD perpendicular to BC and ACD triangle = 10cm² and AC = 9cm Find BC?

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