In a rhombus, if diagonals are 30 cm and 40 cm, find its perimeter.

1.	In a rhombus, if diagonals are 30 cm and 40 cm, find its perimeter.
Answer» Diagonal 30cm = 15cm+15cm (Legs of right triangle within rhombus) Diagonal 40cm = 20cm+20cm (Legs of right triangle within rhombus) We have to find the side of rhombus using pythagorean theorem, Formula to find perimeter, p = 4s s = side of rhombus, 15^2 + 20^2 = s^2 225 + 400 = s^2 625 = s^2 s = 25 Now perimeter of rhombus, = 4s = 425 = 100 Therefore result of perimeter is 100cm

Answer»

Diagonal 30cm = 15cm+15cm (Legs of right triangle within rhombus)

Diagonal 40cm = 20cm+20cm (Legs of right triangle within rhombus)

We have to find the side of rhombus using pythagorean theorem,

Formula to find perimeter, p = 4s

s = side of rhombus,

15^2 + 20^2 = s^2

225 + 400 = s^2

625 = s^2

s = 25

Now perimeter of rhombus, = 4*s

= 4*25 = 100

Therefore result of perimeter is 100cm

Discussion